Final answer:
The question involves determining the throw distance from 3rd base to home plate in softball. Based on the assumption that the softball field is a square with equal sides, and given the area is 3600 ft², the length of one side can be calculated, and hence the distance of a throw from 3rd base to home plate is 60 feet, corresponding with the standard softball diamond measurement.
Step-by-step explanation:
The question asks about the distance of a throw from 3rd base to home plate on a softball field with an area of 3600 ft². Assuming the softball field is a square, as the bases form a diamond which can be inscribed in a square field, each side of the square would be the square root of the area (\(\sqrt{3600 \text{ft}^2}\)), giving us a side length of 60 feet.
To find the distance of the throw from 3rd base to home plate, which is the diagonal of the square, we can use the Pythagorean theorem. If each side of the square is 's', the diagonal 'd' is calculated as
\(d = s\sqrt{2}\). For a side of 60 feet, the diagonal would be:\(60 \times \sqrt{2}\) which equals approximately 84.85 feet. However, since this is not an option, it indicates that either the field is not a square, or there has been a misunderstanding in the question. If we consider the softball field to actually be shaped like a diamond with equal sides, each side being the distance between bases, and not a square, then the throw from 3rd base to home plate would be the length of one side.
As a result, based on the given options, the most logical given choice for the side of a diamond (which is essentially the length of one side of the square), making the throw from 3rd base to home plate 60 feet long, would be option D. This aligns with the standard distance between bases on a regulation adult softball field, which is indeed 60 feet.