Final answer:
The probability that Kyile doesn't win either a game of chess or a game of pool is found by multiplying the individual probabilities of losing each game. If the probabilities of losing the chess and pool games are the same at 0.57, the combined probability of losing both games would be 0.57 multiplied by 0.57, equaling approximately 32.49%.
Step-by-step explanation:
To work out the probability that Kyile doesn't win either a game of chess or a game of pool, we would need to know the probabilities of her winning each game individually. However, let's assume the probability of winning the chess game is pchess and the probability of winning the pool game is ppool. The probability of losing each game would then be 1 - pchess for chess and 1 - ppool for pool.
Since both games are independent events, to find the probability of both losing events happening, we would multiply the probabilities of losing each game:
P(losing both games) = (1 - pchess) × (1 - ppool)
For instance, if the probability of losing a chess game is 0.57 (taken from the provided information), and the probability of losing a pool game is similar, the calculation would be:
P(losing both games) = 0.57 × 0.57 = 0.3249
Therefore, the probability that Kyile does not win either the chess game or the pool game is approximately 32.49%.