Question

What is the heat capacity of a system consisting of a 0.200-kg brass cup filled with 0.0500 kg of water? Specific heats of brass and water at 1.00 atm and 20.0°C are 0.384 kJ/kg·K and 4.186 kJ/kg·K respectively.

Answer 1

The heat capacity of a system consisting of a 0.200-kg brass cup and 0.0500 kg of water is 0.2861 kJ/K, calculated by summing the heat capacities of both the brass and the water. The total heat capacity is Ctotal = 0.2861 kJ/K.

Step-by-step explanation:

The heat capacity of a system consisting of a brass cup and water can be calculated by summing the individual heat capacities of the brass and the water. The formula to calculate heat capacity (C) is:

C = mass (m) × specific heat capacity (c)

For brass:

Cbrass = mbrass × cbrass

Cbrass = 0.200 kg × 0.384 kJ/kg·K

Cbrass = 0.0768 kJ/K

For water:

Cwater = mwater × cwater

Cwater = 0.0500 kg × 4.186 kJ/kg·K

Cwater = 0.2093 kJ/K

Therefore, the total heat capacity of the system is:

Ctotal = Cbrass + Cwater

Ctotal = 0.0768 kJ/K + 0.2093 kJ/K

Ctotal = 0.2861 kJ/K