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A car accelerates on a straight road from rest to 75kml h in 5.0 s what is the magnitude of average accommodation

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Final answer:

The average acceleration of a car that goes from rest to 75 km/h in 5.0 seconds is 4.17 m/s², after converting the speed from km/h to m/s.

Step-by-step explanation:

The student has asked what the magnitude of the average acceleration of a car is when it accelerates from rest to 75 km/h in 5.0 seconds. To find the average acceleration, we first convert the speed from km/h to m/s. Since 1 km/h is equal to 0.27778 m/s, 75 km/h equals approximately 20.83 m/s (75 * 0.27778). The formula for average acceleration (a) is a = Δv / t, where Δv is the change in velocity and t is the time taken. Here, Δv = 20.83 m/s (final velocity) - 0 m/s (initial velocity) = 20.83 m/s. So, the average acceleration is a = 20.83 m/s / 5.0 s = 4.17 m/s².

CORRECT QUESTION:

A car accelerates on a straight road from rest to 75kml h in 5.0 s. What is the magnitude of average acceleration.

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