Question

A boy standing on a 49.9 m tall cliff throws a rock up in the air with an initial velocity of 27.5 m/s. how much time (in s) will the rock take to reach the water below?

Answer 1

The rock will take approximately 8.8 seconds to reach the water below.

Step-by-step explanation:

To find the time it takes for the rock to reach the water below, we first need to determine the height of the cliff. We can use the equation:

h = (v^2) / (2g)

where h is the height of the cliff, v is the initial velocity of the rock, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Plugging in the values:

h = (27.5^2) / (2 * 9.8)

h = 379.7 m

Now, we can use the equation:

t = sqrt((2h) / g)

where t is the time it takes for the rock to reach the water.

Plugging in the values:

t = sqrt((2 * 379.7) / 9.8)

t = sqrt(77.4)

t ≈ 8.80 s