Final answer:
The cliff diver was traveling at an initial speed of 6 feet/second when entering the water.
Step-by-step explanation:
The subject of this question is Physics. The question involves the calculation of the initial speed of a cliff diver when entering the water.
To find the initial speed, we can use the equation:
v0 = d / t
where v0 is the initial speed, d is the distance traveled (the depth of the water), and t is the time taken.
Given that the cliff diver descends to a depth of 12 feet below the surface and the time taken is 2.00 seconds, we can substitute the values into the equation:
v0 = 12 feet / 2.00 seconds = 6 feet/second
Therefore, the cliff diver was traveling at an initial speed of 6 feet/second when entering the water.