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The number of bacteria in a petri dish on the first daywas 252 cells. If the number of bacteria increase at arate of 57% per day, how many bacteria cells will therebe after 7 days?y = 252(0.57|) ²What number will you fill in for a to solve the equation?7y=

User PedroMorgan
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1 Answer

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22 votes

Answer:


\begin{gathered} y=252*1.57^x \\ y=5925\text{ cells} \end{gathered}

Explanation:

The exponential function is represented by the following equation:


y=ab^x

where a is the initial amount and b is the change factor per unit time, therefore if it creases by 57% per day and the initial amount was 252 cells:


y=252*1.57^x

To determine the population after 7 days, substitute x=7:


\begin{gathered} y=252*1.57^7 \\ y=5925\text{ cells} \end{gathered}

User Aavik
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