Question

The perimeter of a rectangle is 44 meters and the length is 10 meters more than twice the width. Find the dimensions.18 meters and 4 meters6 meters and 9 meters5 meters and 9 meters6 meters and 16 meters

Answer 1

Given:

The perimeter of a rectangle is 44 meters.

The length is 10 meters more than twice the width.

Required:

To find the dimensions.

Step-by-step explanation:

The perimetero of rectangle formula is

`P=2(L+W)`

Let x be the width.

The length is 10 meters more than twice the width.

So

`L=2x+10`

Now

`\begin{gathered} P=2(2x+10+x) \\ \\ 44=4x+20+2x \\ \\ 44=6x+20 \\ \\ 6x=44-20 \\ \\ 6x=24 \\ \\ x=(24)/(6) \\ \\ x=4m \end{gathered}`

Here the width is 4m.

Now the length is

`\begin{gathered} L=2(4)+10 \\ =8+10 \\ =18m \end{gathered}`

Final Answer:

18 meters and 4 meters.