Final answer:
In a RAID-5 left-asymmetric placement system, logical block number 23 with a chunk size of 2 blocks is placed on the second disk.
Step-by-step explanation:
In a RAID-5 left-asymmetric placement system, data is distributed across disks in a left-to-right manner. Each logical block is divided into chunks, and each chunk is placed on a different disk in a round-robin fashion. The placement starts with the leftmost disk and continues until all disks are used, after which the placement wraps around to the leftmost disk.
In this case, with a chunk size of 2 blocks and logical block number 23, we need to determine the disk on which this block is placed. Since each chunk is made up of 2 blocks, we can calculate how many chunks have been assigned to disks before block 23. Dividing 23 by 2 gives us 11 chunks. Since the placement wraps around to the first disk, we need to find the remainder of 11 divided by the number of disks in the RAID system, which is 5. The remainder is 1, so logical block number 23 is placed on the second disk in the RAID system.