Question

A 142 n block sits on a rough horizontal floor. the coefficient of sliding friction between the block and the floor is 0.008. a horizontal force of 103 n acts on the block for 2 seconds. calculate the velocity of the block after 2 seconds if it starts from rest. (use 9.8 ™ for g; round answers to 3 decimal places)

Answer 1

The velocity of the block after 2 seconds is 1.45 m/s.

Step-by-step explanation:

To calculate the velocity of the block after 2 seconds, we need to consider the forces acting on it. The horizontal force of 103 N will create an acceleration, which we can find using Newton's second law of motion: acceleration = force / mass.

The mass of the block is given as 142 N, so we have acceleration = 103 N / 142 N = 0.725 m/s². After 2 seconds, the velocity of the block can be found using the equation: final velocity = initial velocity + (acceleration * time). Since the block starts from rest, the initial velocity is 0, so the final velocity is 0 + (0.725 m/s² * 2 s) = 1.45 m/s.