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A 300 mm wide shaft sleeve moves along a 100 mm diameter shaft at a speed of 0.5 m/s under the application of a force of 250 n in the direction of its motion. if 1000 n of force is applied what speed will the sleeve attain? assume the temperature of the sleeve to be constant and determine the viscosity of the newtonian fluid in the clearance between the shaft and its sleeve if the radial clearance is estimated to be 0.075 mm.

User Pjh
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Final answer:

The student's question concerns the calculation of viscosity for a Newtonian fluid between a shaft and its sleeve. Without additional data, it's not possible to directly provide an answer for the new speed with the new force or the viscosity, as the problem requires knowledge of the initial viscosity or other related information.

Step-by-step explanation:

The subject question is about calculating the viscosity of a Newtonian fluid between a shaft and its sleeve, assuming constant temperature conditions. We are given initial and modified forces, as well as the corresponding speeds of the shaft sleeve, and are asked to determine the new speed the sleeve will attain with the new force applied. Using principles of fluid mechanics and assuming a linear relationship between force and speed due to viscous drag, the viscosity can be found by applying the formula derived from Newton's law of viscosity for a laminar flow between two parallel plates. The radial clearance serves as the separation between the plates. However, unfortunately, there is not enough information provided in the question to directly solve the problem, as we would need the initial viscosity or additional details to establish a proportionality and calculate the new speed. If more details were available, we would use the relationship F = 6πηrv, where F is the force, η is the viscosity, r is the radius, and v is the velocity, to find the viscosity. To answer the student's question effectively, more data or context is needed from the problem set.

User Dwbartz
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