Question

A 4.0 kg k g pendulum bob swings on a 2-m m -long string. the bob's speed is 3.0 m/s m / s when the string makes a 35 ∘ ∘ angle with vertical and the bob is moving toward the bottom of the arc. what is the tangential acceleration?

Answer 1

The tangential acceleration of the pendulum bob is 1.2218 m/s².

Step-by-step explanation:

The tangential acceleration of a swinging pendulum bob can be found using the formula:

at = Rθ^2

Where at is the tangential acceleration, R is the length of the string, and θ is the angle the string makes with the vertical.

Using the given information, we have:

R = 2 m (length of the string)

θ = 35° (angle with vertical)

Substituting these values into the formula:

at = (2 m)(35°)^2

at = 2 m × (0.6109)

at = 1.2218 m/s²

Therefore, the tangential acceleration of the pendulum bob is 1.2218 m/s².