Question

A 25 ml volume of hcl solution of unknown concentration is titrated with .1 m naoh solution neutralization of the hcl solution requires 28.6 ml of the nao solution calculate the concentration of the hcl solution

Answer 1

To determine the HCl concentration, the titration equation c1 × V1 = c2 × V2 is used, where c1 is the concentration of HCl, V1 the volume of HCl, c2 the concentration of NaOH, and V2 the volume of NaOH. The concentration of the HCl solution is calculated to be 0.1144 M.

Step-by-step explanation:

To calculate the concentration of the HCl solution, we employ the concept of titration. Given that 25 ml of HCl are neutralized by 28.6 ml of 0.1 M NaOH, we can use the equation:

c1 × V1 = c2 × V2

where c1 and V1 are the concentration and volume of HCl, respectively; and c2 and V2 are the concentration and volume of NaOH, respectively.

Since the molarity (M) of NaOH is 0.1 and the volume (V2) is 28.6 ml (or 0.0286 L), we can substitute these values along with the volume of HCl (V1 = 0.025 L) into the equation:

c1 × 0.025 L = 0.1 M × 0.0286 L

Solving for c1 gives us:

c1 = (0.1 M × 0.0286 L) / 0.025 L

Therefore, the concentration of the HCl solution is 0.1144 M.