Question

A 10.0 ml sample of h2so4 is titrated with 0.512 m naoh. the initial buret volume is 0.10 ml and the final buret volume is 24.83 ml. what is the concentration (mol/l) of the h2so4 sample? answer to 3 decimal places with no units.

Answer 1

The concentration of the H2SO4 sample is calculated by dividing the moles of NaOH used in the titration by 2 (due to the 1:2 reaction ratio with H2SO4) and then dividing by the volume of the H2SO4 sample. Using the provided volumes and molarity of NaOH, the concentration of H2SO4 is found to be 0.633 mol/L.

Step-by-step explanation:

To determine the concentration of the H2SO4 sample, you must first calculate the moles of NaOH used in the titration. The volume of NaOH used is found by subtracting the initial buret volume (0.10 mL) from the final buret volume (24.83 mL), which gives 24.73 mL or 0.02473 liters. Multiply this by the concentration of the NaOH solution (0.512 M) to find the moles of NaOH:

0.02473 L × 0.512 mol/L = 0.01265536 mol NaOH

Since the reaction between H2SO4 and NaOH is a 1:2 ratio as shown in the reaction H2SO4 (aq) + 2NaOH(aq) → Na2SO4 (aq) + 2H2O(l), divide the moles of NaOH by 2 to find the moles of H2SO4:

0.01265536 mol NaOH × (1 mol H2SO4/2 mol NaOH) = 0.00632768 mol H2SO4

Then, divide the moles of H2SO4 by the volume of H2SO4 sample in liters (10.0 mL is 0.010 liters) to find the molarity of H2SO4:

0.00632768 mol H2SO4 / 0.010 L = 0.633