Question

A 1.1 cm3 air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 2.0 atm . the bubble rises slowly enough that the air inside remains at the same constant temperature as the water. part a what is the volume of the bubble as it reaches the surface?

Answer 1

Using Boyle's Law, the 1.1 cm³ air bubble released from the bottom of the sea at 2.0 atm will have a volume of 2.2 cm³ when it reaches the surface, assuming constant temperature and that the pressure at the surface is 1 atm.

Step-by-step explanation:

The question pertains to the behavior of gases under different pressures using the combined gas law. When a 1.1 cm³ air bubble is released from the bottom of the sea at a gauge pressure of 2.0 atm, and as it rises, the pressure decreases until it reaches the surface where the pressure is 1 atm (standard atmospheric pressure). Assuming the temperature remains constant, the volume of the bubble at the surface can be calculated using Boyle's Law, which states that pressure is inversely proportional to volume (P1V1 = P2V2).

Let V2 be the volume of the bubble at the surface. We can set up the equation as (2.0 atm)(1.1 cm³) = (1.0 atm)(V2), which simplifies to V2 = (2.0 atm / 1.0 atm) × (1.1 cm³), resulting in V2 = 2.2 cm³. Therefore, at the surface, the bubble's volume will be 2.2 cm³.