Final answer:
The most strongly attracted molecule to a Cl- ion would be a) H-F due to the ion-dipole force.
Step-by-step explanation:
The most significant intermolecular force in this case would be the ion-dipole force. An ion-dipole force occurs when a charged ion is attracted to the partial charges on the polar end of a molecule. In this case, the Cl- ion would be attracted to the partial positive charges on the H-F molecule.
Let's analyze the options given:
a. H-F: This is a polar molecule with a partial positive charge on the hydrogen atom and a partial negative charge on the fluorine atom. Therefore, the Cl- ion would be most strongly attracted to H-F.
b. F-F: This is a nonpolar molecule with no partial charges. The Cl- ion would not be attracted to F-F.
c. CCl4: This is a nonpolar molecule with no partial charges. The Cl- ion would not be attracted to CCl4.
d. Cl-Cl: This is a nonpolar molecule with no partial charges. The Cl- ion would not be attracted to Cl-Cl.