108k views
5 votes
Write a general formula to describe the variation: m varies jointly with the inverse of the square of b and directly with the cube of b. m = kb3b2

User Kakridge
by
7.4k points

1 Answer

2 votes

Final answer:

The general formula for the variable m that varies jointly with the inverse of the square of b and directly with the cube of b simplifies to m = k*b, where k is the constant of proportionality.

Step-by-step explanation:

The question asks for the general formula to describe a variable m that varies jointly with the inverse of the square of b and directly with the cube of b. To represent this relationship mathematically, we use a constant of proportionality k. The variation can be denoted as m = k*(1/b^2)*b^3, which simplifies to m = k*b. Hence, the variational equation shows that m is directly proportional to b, altered by a constant k.

It is important to notice that when we multiply the inverse of the square of b (1/b^2) with the cube of b (b^3), the exponents add up algebraically (since one exponent is negative), resulting in b^(3-2) = b^1, which is simply b. This relationship is based on the laws of exponents, which allow us to simplify exponential expressions.

User Erez Hochman
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories