Question

To what volume should you dilute 127 ml of an 7.95 m cucl2 solution so that 48.5 ml of the diluted solution contains 4.85 g cucl2 ? express your answer in milliliters.

Answer 1

The volume to which you should dilute 127 mL of a 7.95 M CuCl2 solution so that 48.5 mL of the diluted solution contains 4.85 g CuCl2 is 1357 mL.

Step-by-step explanation:

To determine the volume to which you should dilute 127 mL of a 7.95 M CuCl2 solution so that 48.5 mL of the diluted solution contains 4.85 g CuCl2, you must first calculate how many moles of CuCl2 are in 4.85 g. The molar mass of CuCl2 is 134.45 g/mol (Cu = 63.55 g/mol, Cl = 35.45 g/mol × 2). To find the moles, you divide the mass by the molar mass:

Moles of CuCl2 = 4.85 g / 134.45 g/mol = 0.03606 mol

The concentration (C2) of the diluted solution can then be calculated using the volume (V2) that contains the measured amount of substance:

C2 = moles of solute / volume of solution in liters = 0.03606 mol / 0.0485 L = 0.7435 M

Using the dilution formula C1V1 = C2V2, where C1 is the initial concentration and V1 is the initial volume, we can solve for the final volume (V2):

7.95 M × 0.127 L = 0.7435 M × V2

V2 = (7.95 M × 0.127 L) / 0.7435 M = 1.357 L or 1357 mL