Question

Pete slides a crate up a ramp at an angle of 25◦ by exerting a 241 n force parallel to the ramp. the crate moves at a constant speed. the coefficient of friction is 0.14. how much work did pete do when the crate was raised a vertical distance of 1.8 m? answer in units of j.

Answer 1

To calculate the work done by Pete on the crate, use the vertical distance and the angle of the ramp to find the length of the ramp. Then multiply the force exerted by Pete with this distance to find the work done, expressed in Joules.

Step-by-step explanation:

To calculate the work done by Pete on the crate that was raised a vertical distance of 1.8 m, we have to consider the relationship between the vertical height and the length of the ramp, which can be determined by the angle of the incline. Using trigonometry, we can calculate the length of the ramp using the sine of the angle of incline (sin(25°)) and the vertical distance (1.8 m). Then, the work done by Pete is the force exerted (241 N) multiplied by the distance moved along the ramp (which we calculated from the vertical height and angle).

The coefficient of friction is not relevant in calculating the work done unless asked for the work done against the frictional force. Since the crate is moving at a constant speed, this implies that the net work done against friction is equal to zero, and thus, we only consider Pete's input work in moving the crate up the ramp. Therefore, the work done by Pete (W) is given by:

W = Force * Distance = 241 N * (Vertical Distance / sin(25°))

Upon calculating the distance and then the work, we express the final answer in units of Joules (J).