Question

Dolphin jump y = -16x2 32x - 10 this parabola has x-intercepts, representing the times when the dolphin's height above water is feet. on a coordinate plane, a parabola opens down. time (seconds) is on the x-axis and height (feet) is on the y-axis. it goes through (0, negative 10), has a vertex at (1, 6), and goes through (2, negative 10).

Answer 1

To find the height the dolphin rises above the water, use the equation y = Voyt - 1/2gt^2. The maximum height is 10.3 meters. To find the time the dolphin is in the air, set y = 0 and solve the equation.

Step-by-step explanation:

This question is about the trajectory of a dolphin jumping out of the water. The known information includes the initial velocity of the dolphin, which is 13.0 m/s. To find out how high the dolphin rises above the water, we need to solve for the unknown, which is the maximum height. We can use the equation y = Voyt - 1/2gt^2 to find the height. After substituting the known values and solving for y, we find that the dolphin rises to a height of 10.3 meters above the water.

To determine how long the dolphin is in the air, we can use the equation y = Voyt - 1/2gt^2 and find the time when the height is zero. By solving the quadratic equation, we find that the dolphin is in the air for approximately 2.65 seconds.