Question

An 80-kg person stands at rest on a scale while pulling vertically downward on a rope that is hanging at rest directly above, as shown here. use g = 9.80 m/s2. with what force magnitude must the rope's tension be pulling on the person so that the scale reads 25% of the person's weight?

Answer 1

The tension in the rope must be 196 N.

Step-by-step explanation:

To find the force magnitude needed for the rope's tension to read 25% of the person's weight on the scale, we can use the equation:

T = mg

where T is the tension, m is the mass of the person, and g is the acceleration due to gravity. In this case, the person's weight is equal to mg, so we can set up the equation:

T = (0.25)(mg)

Substituting the known values:

T = (0.25)(80 kg)(9.80 m/s²) = 196 N

Therefore, the rope's tension must be 196 N so that the scale reads 25% of the person's weight.