Question

Air enters a compressor operating at steady state at 1.05bar, 300k, with a volumetric flow rate of 30m³/min and exits at 12bar, 400k. heat tranfer occurs at a rate of 5kw from the compressor to its surroundings.

Answer 1

Step-by-step explanation:

The given problem provides information about the operating conditions of a compressor and the heat transfer rate between the compressor and its surroundings. Let's break down the information and analyze it step by step:

1. Air enters the compressor at a pressure of 1.05 bar and a temperature of 300 K. The volumetric flow rate of the air is given as 30 m³/min.

2. The air exits the compressor at a pressure of 12 bar and a temperature of 400 K.

3. Heat transfer occurs between the compressor and its surroundings at a rate of 5 kW.

Based on this information, we can make the following observations:

- The pressure of the air increases from 1.05 bar to 12 bar as it passes through the compressor.

- The temperature of the air also increases from 300 K to 400 K.

- The heat transfer rate from the compressor to its surroundings is 5 kW.

To fully answer the question, we need to determine the work done by the compressor. This can be calculated using the equation:

Work done = Change in enthalpy = mass flow rate * (enthalpy at exit - enthalpy at inlet)

Since the mass flow rate is not given in the problem, we cannot calculate the exact value of the work done by the compressor. However, we can provide a general understanding of the concept and the equation needed to calculate the work done.

In this case, the work done by the compressor represents the energy required to increase the pressure and temperature of the air. As the air passes through the compressor, its pressure and temperature increase, and work is done on the air by the compressor.

To summarize, the problem provides information about the operating conditions of a compressor and the heat transfer rate between the compressor and its surroundings. The pressure and temperature of the air increase as it passes through the compressor. The work done by the compressor can be calculated using the equation: Work done = mass flow rate * (enthalpy at exit - enthalpy at inlet). However, since the mass flow rate is not given, we cannot calculate the exact value of the work done in this problem.

Answer 2

The question deals with the operation of an air compressor and requires knowledge of thermodynamics to find work done by the compressor and heat transfer, applying the first law of thermodynamics.

Step-by-step explanation:

The question pertains to an air compressor operating in a steady state and involves thermodynamics, a branch of physics that deals with the relationships between heat and other forms of energy. Specifically, it addresses the topics of work, heat transfer, and the thermodynamic properties of air from its entry to its exit in a compression process. In this case, air enters a compressor at 1.05 bar and 300 K, exits at 12 bar and 400 K, with a volumetric flow rate of 30 m³/min, and heat is being transferred to the surroundings at a rate of 5 kW.

The analysis would typically involve using the first law of thermodynamics for an open system (a control volume) and may require additional information such as the specific heats of air, depending on the level of detail required for the solution. To determine the energy balance of the compressor, we might use equations related to the conservation of mass and conservation of energy. These principles would allow us to calculate the work done by the compressor and other properties of interest.