Final answer:
The probability that at least one of the three randomly selected people is left-handed is 0.428213.
Step-by-step explanation:
To find the probability that at least one of the three randomly selected people is left-handed, we can calculate the probability that none of them are left-handed and subtract it from 1. Since 17% of the population is left-handed, the probability that a randomly selected person is left-handed is 0.17. Therefore, the probability that a randomly selected person is right-handed is 1 - 0.17 = 0.83.
Now, to find the probability that none of the three selected people are left-handed, we multiply the probability of selecting a right-handed person by itself three times since the selections are independent:
P(no left-handed people) = (0.83)^3 = 0.571787.
Finally, to find the probability that at least one of the three selected people is left-handed, we subtract the probability of none of them being left-handed from 1:
P(at least one left-handed person) = 1 - 0.571787 = 0.428213.