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A uniform electric field of magnitude 366 v/m is directed in the positive x-direction. suppose a 16 µc charge moves from the origin to point a at the coordinates, (36 cm, 58 cm).

User Nazira
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Final answer:

The problem requires calculating the change in electric potential energy as a 16 µC charge moves in a uniform electric field directed along the x-axis, using the formula ΔU = qEd.

Step-by-step explanation:

The question involves calculating the electric potential energy change and work done on a charge moving in a uniform electric field. Here, we use the equation ΔU = qEd, where ΔU is the change in electric potential energy, q is the charge, E is the electric field's magnitude, and d is the displacement in the direction of the field. In this case, we're only interested in the x-component of the displacement since the electric field is directed in the positive x-direction. Thus, the change in potential energy is given by ΔU = (16 × 10-6 C) × (366 V/m) × (0.36 m), which results in a value in joules (J).

User Sistina
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