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A waste treatment lagoon is 50 meters long and 15 meters wide with an average depth of 2 meters. the density of wastewater is 1.03 g/cm3 . calculate the mass (kg) and weight (n) of the pond.

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Final answer:

The mass of the wastewater in the lagoon is 1,545,000 kg and the weight is 15,156,450 N, calculated using the volume of the lagoon and the density of wastewater.

Step-by-step explanation:

To calculate the mass of the wastewater in the treatment lagoon, we need to find the volume of the lagoon and then multiply it by the density of the wastewater. The volume (V) of the lagoon is the product of its length (L), width (W), and average depth (D), which gives: V = L × W × D = 50 m × 15 m × 2 m = 1500 m³. Since the density (ρ) of wastewater is 1.03 g/cm³ (which is equivalent to 1030 kg/m³), the mass (m) is calculated by multiplying the volume by the density: m = V × ρ = 1500 m³ × 1030 kg/m³ = 1,545,000 kg.

To find the weight (W) of the wastewater, we use the equation W = m × g, where g is the acceleration due to gravity (approximately 9.81 m/s²). Therefore, W = 1,545,000 kg × 9.81 m/s² = 15,156,450 N (newtons).

Both the mass and the weight have been calculated assuming standard gravity and a uniform density of the wastewater.

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