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Multiply ((x^2-25)/(x^2+6x+5))*((x^2-2x-3)/(x^2-3x -10)). State any restrictions on the variables.

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Final answer:

To multiply the given fractions, factor each polynomial, cancel out the common factors, and find the simplified expression. The expression simplifies to (x - 3)/(x + 2), with restrictions that x cannot be -5, -1, 5, or -2, as these values would make the original denominators zero.

Step-by-step explanation:

The question asks to multiply two fractions and find any restrictions on the variables. The fractions are:

((x^2-25)/(x^2+6x+5)) * ((x^2-2x-3)/(x^2-3x-10)).

To multiply these fractions, you can first factor each polynomial:

  • x^2 - 25 = (x + 5)(x - 5)
  • x^2 + 6x + 5 = (x + 5)(x + 1)
  • x^2 - 2x - 3 = (x - 3)(x + 1)
  • x^2 - 3x - 10 = (x - 5)(x + 2)

Multiplying the factored forms, you get:

((x + 5)(x - 5))/((x + 5)(x + 1)) * ((x - 3)(x + 1))/((x - 5)(x + 2)).

Simplifying the expression by canceling out common factors, we are left with:

(x - 3)/(x + 2).

The restrictions on the variable x are that x cannot take values that make the denominator of any original fraction equal to zero. Therefore, x cannot be -5, -1, 5, or -2.

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