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What is the polar form of Vm sin (ωt + θ)?

User Friherd
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Final answer:

The polar form of Vm sin (ωt + θ) is Vm cis(θ), where Vm represents the magnitude and θ is the argument or phase angle.

Step-by-step explanation:

The polar form of Vm sin (ωt + θ) can be expressed as:

Vm cis(θ)

where Vm represents the magnitude of the complex number and θ is the argument or phase angle.

For example, if Vm = 5 and θ = 60°, the polar form would be 5 cis(60°).

User Interface Unknown
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