Question

Given the following balance equation: N2 + 3 H2 -----> 2 NH3 Find the number of mole of ammonia that can be produced by combining excess nitrogen with 5.6 mols of hydrogen.

Answer 1

To calculate the number of moles of ammonia produced from 5.6 moles of hydrogen, use the mole ratio from the balanced equation, which is 3 moles of H2 to 2 moles of NH3. This results in 3.73 moles of NH3 being produced.

Step-by-step explanation:

The question involves finding the number of moles of ammonia (NH3) that can be produced when combining an excess of nitrogen (N2) with a specific amount of hydrogen (H2). According to the balanced chemical equation, N2 + 3 H2 → 2 NH3, the mole ratio of hydrogen to ammonia is 3:2. This means that 3 moles of hydrogen will produce 2 moles of ammonia. If we have 5.6 moles of hydrogen, the number of moles of ammonia produced can be calculated by setting up a proportional relationship.

To calculate the moles of ammonia from hydrogen, we use the ratio from the balanced equation:

3 moles of H2 produce 2 moles of NH3.

If we have 5.6 moles of H2:

(5.6 moles H2) x (2 moles NH3 / 3 moles H2) = 3.73 moles of NH3

Therefore, by combining 5.6 moles of hydrogen with an excess of nitrogen, you would be able to produce 3.73 moles of ammonia.