Final answer:
To determine the volume of 70.0 g of fluorine gas at STP, calculate the number of moles using the molar mass of F2 and then multiply by 22.4 L, the volume occupied by one mole of gas at STP, resulting in a volume of approximately 41.263 L.
Step-by-step explanation:
To find the volume of 70.0 g of fluorine gas (F2) at standard temperature and pressure (STP), we first need to determine the number of moles of fluorine gas. The molar mass of F2 is approximately 38.00 g/mol. Therefore, the number of moles of F2 is calculated as:
70.0 g F2 × (1 mol F2 / 38.00 g) = 1.8421 mol F2
At STP, which is defined as 0°C and 1 atm pressure, one mole of any ideal gas occupies a fixed volume of 22.4 L. Therefore, the volume of fluorine gas is:
1.8421 mol F2 × 22.4 L/mol = 41.263 L