Final answer:
To find the pressure of the oxygen gas in the cylinder, we can use the ideal gas law equation PV = nRT. By converting the mass of the oxygen gas to moles and plugging in the values, we find that the pressure is approximately 6.64 atm.
Step-by-step explanation:
To determine the pressure of the oxygen gas in the cylinder, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant
T = temperature of the gas
First, we need to convert the mass of the oxygen gas to moles. The molar mass of oxygen (O₂) is 32 g/mol. So, the number of moles (n) can be calculated as:
n = mass / molar mass
n = 51.3 g / 32 g/mol = 1.603 mol
Next, we can rearrange the ideal gas law equation to solve for the pressure:
P = nRT / V
Plugging in the values:
P = (1.603 mol)(0.0821 L·atm/mol·K)(296 K) / 8.58 L = 6.64 atm
Therefore, the pressure of the oxygen gas in the cylinder is approximately 6.64 atm.