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Find the slope of a line perpendicular to the line whose equation is 6, x, plus, 5, y, equals, minus, 306x+5y=−30. Fully simplify your answer.

User Doris Liu
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Final answer:

The slope of a line perpendicular to the line with equation 6x + 5y = -30 is 5/6, which is the negative reciprocal of the original line's slope.

Step-by-step explanation:

To find the slope of the line perpendicular to the line represented by the equation 6x + 5y = -30, we need to manipulate the equation into slope-intercept form, which is y = mx + b, where m represents the slope, and b represents the y-intercept. First, let's solve for y:

  • 6x + 5y = -30
  • 5y = -6x - 30
  • y = -(6/5)x - 6

The slope of this line is -6/5. The slope of a line perpendicular to this would be the negative reciprocal of -6/5, which is 5/6. Hence, the slope of the perpendicular line is 5/6.

User Soid
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