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The minimum depth for a 120-volt, 15-ampere, GFCI-protected circuit to an outdoor pole light run under a paved driveway is

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Final answer:

The 1800-W toaster draws 15 A, the 1400-W electric frying pan draws 11.67 A, and the 75-W lamp draws 0.625 A. The total current drawn by all devices is 27.295 A, which exceeds the circuit's 15-A limit and will blow the fuse.

Step-by-step explanation:

To determine the current drawn by each device, we use the power formula for an electric circuit: Power (W) = Voltage (V) × Current (I). To find the current drawn by the devices, rearrange the formula to Current (I) = Power (W) / Voltage (V):

For the 1800-W toaster: I = 1800 W / 120 V = 15 A.

For the 1400-W electric frying pan: I = 1400 W / 120 V = 11.67 A.

For the 75-W lamp: I = 75 W / 120 V = 0.625 A.

Summing up these currents: 15 A + 11.67 A + 0.625 A = 27.295 A, which exceeds the circuit's 15-A capacity. Thus, this combination will indeed blow the 15-A fuse.

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