Final answer:
To calculate the molarity, the mass of NaNO3 is found by multiplying moles by molar mass, summing it with the mass of water to get total mass, then using density to find volume. Dividing moles of NaNO3 by volume in liters gives a molarity of 1.366 M.
Step-by-step explanation:
The question is about calculating the molarity of a solution after mixing a certain number of moles of NaNO3 with a given mass of water. The molarity (M) is the number of moles of solute per liter of solution. To find the molarity, we will first determine the mass of NaNO3 and the total mass of the solution to calculate the volume of the solution, using the provided density.
The mass of NaNO3 is calculated by multiplying the number of moles by the molar mass:
(0.3355 moles) × (84.995 g/mol) = 28.512 g NaNO3
Adding the mass of the water, the total mass of the solution is:
28.512 g + 235.0 g = 263.512 g
To find the volume in liters, we use the density:
Volume = Mass / Density
Volume = 263.512 g / (1.0733 g/mL) = 245.569 mL = 0.245569 L
Now we divide the number of moles of NaNO3 by the total volume of the solution in liters to get the molarity:
Molarity = Moles of solute / Volume of solution in liters
Molarity = 0.3355 moles / 0.245569 L = 1.366 M
The molarity of the NaNO3 solution is therefore 1.366 M.