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How much does a column of water weigh ( in pounds ) that occupies i square foot and is 10 feet high ?

User Ntownsend
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Final answer:

The weight of a column of water, having a 1 square foot base and being 10 feet tall, would be 624 pounds, considering the density of water to be 62.4 pounds per cubic foot.

Step-by-step explanation:

The question asks how much a column of water weighs that is 1 square foot in area and 10 feet high. To calculate the weight, we need to know the density of water, which is typically about 62.4 pounds per cubic foot. As we are dealing with a 10-foot high column of 1 square foot in area, the volume of water in cubic feet is simply area \(\times\) height, which equals 10 cubic feet. To find the weight, we multiply the volume by the density:

  • Volume = 1 sq. foot \(\times\) 10 feet = 10 cubic feet
  • Weight = Volume \(\times\) Density = 10 cubic feet \(\times\) 62.4 pounds/cubic foot

Therefore, the weight of the column of water would be 624 pounds.

User Joeklieg
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