Question

What is wrong with:

int s = Math.sqrt(49);

Answer 1

The code is assigning a double value to an integer variable. The variable should be changed to double.

Step-by-step explanation:

The error in the code is that the Math.sqrt function returns a double value, but the result is being assigned to an integer variable.

To fix this, you should change the data type of the variable s to double instead of int.

Here is the corrected code:

double s = Math.sqrt(49);