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Given the following code, what would be the value stored in the Double object referenced by the variable d?

int x = 7;
Double d = new Double(x);

2 Answers

3 votes

Final answer:

In Java, when an integer value is passed to the Double object constructor, it is automatically converted to a double. Therefore, the Double object 'd' will hold the value 7.0.

Step-by-step explanation:

The student has asked about the value stored in a Double object when it is instantiated with an integer value in Java.

In this code snippet:

int x = 7;

Double d = new Double(x);

The variable x is an integer with a value of 7.

When we create a new Double object and pass the integer variable x to the constructor, Java will automatically convert the integer to a double.

Thus, the value stored in the Double object referenced by the variable d will be 7.0.

User Honza R
by
8.9k points
2 votes

Final answer:

The code snippet creates a Double object with the value 7.0 from an int value of 7.

Step-by-step explanation:

The question asks what the value stored in the Double object, referenced by the variable d, would be given the provided code snippet.

The code defines an integer x with a value of 7 and then creates a new Double object with x as the constructor argument.

When a new Double object is created using an int as the argument, Java automatically converts the int to a double primitive value and stores it in the Double object.

Thus, the value of the Double object referenced by d will be 7.0.

The complete question is:

Given the following code, what would be the value stored in the Double object referenced by the variable d?

int x = 7;

Double d = new Double(x);

User JasonS
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8.0k points