Question

What would be printed by the following code?

double y = 4.7;
Integer n = new Integer((int) y);
System.out.println(n);

Answer 1

The Java code will print the integer value 4 by truncating the decimal part of the double value 4.7 and boxing the integer value into an Integer object.

Step-by-step explanation:

The student's question pertains to what output would be produced by a given piece of Java code. In the code, a double variable y is initialized with the value 4.7. The code then creates an Integer object n by casting the double to an int, which results in truncating the decimal part, leaving only the integer value 4 to be boxed into the Integer object. Finally, the System.out.println(n) statement prints out the value of the Integer object n to the console.

The output would be:4The code snippet will print the value 4. The variable 'y' is declared as a double and assigned the value 4.7. Next, a new Integer object 'n' is created using the 'new Integer()' constructor. The 'int' value of 'y' is cast to an integer using '(int) y' and then stored in 'n'. When 'n' is printed using 'System.out.println()', it will display the value 4.