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A gas at 350 K and 12 atm has a molar volume 12 percent points larger than that calculated from the perfect gas law. Calculate (i) the compression factor under these conditions and (ii) the molar volume of the gas. (iii) Which are dominating in the gas, the attractive or the repulsive force? Hint: You need to calculate the molar volume of the perfect gas under the same condition first and assume the gas constant is 0.082 dm3 atm / mol K.

User Oyarzun
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Final answer:

To calculate the compression factor and molar volume of a gas at given conditions, use the ideal gas law and the formula for molar volume. The dominating force in the gas can be determined by comparing the compression factor to 1.

Step-by-step explanation:

To calculate the compression factor under the given conditions, we can use the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Rearranging the equation to solve for the compression factor (Z):

Z = PV/(nRT)

Substituting the given values for pressure, temperature, and molar volume, we can calculate Z. For the molar volume of the gas, we can use the equation:

V = V_predicted + (V_predicted * percent_increment/100)

Substituting the given values, we can calculate the molar volume. To determine whether the attractive or the repulsive force is dominating in the gas, we need to compare Z to 1. If Z is greater than 1, the repulsive force is dominating; if Z is less than 1, the attractive force is dominating.

User Pravanjan
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