Question

A solution is prepared by dissolving 23.7g of CaCl2 in 375g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl2 in this solution is ________ molal.

Answer 1

The concentration of CaCl2 in the solution is 0.608 mol/kg.

Step-by-step explanation:

To calculate the concentration of CaCl2 in the solution, we need to first convert the mass of CaCl2 to moles. The molar mass of CaCl2 is 110.98 g/mol, so 23.7 g of CaCl2 is equal to 23.7 g / 110.98 g/mol = 0.2137 mol. Next, we need to calculate the mass of water in the solution by subtracting the mass of CaCl2 from the total mass of the solution: 375 g - 23.7 g = 351.3 g. Finally, we can calculate the molality of CaCl2 by dividing the moles of solute (CaCl2) by the mass of water in kg:

Molality = moles of solute / mass of water (in kg) = 0.2137 mol / 0.3513 kg = 0.608 mol/kg.