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The dimensions of a window are 5x+5 and 2x+6. What is the area of the window?

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Our answer is 10x^2 + 40x + 30.


\Large\texttt{Explanation}

We are asked to find the area of a window, given that:

  • its length is 5x + 5
  • its width is 2x + 6

The formula for a rectangle's area (assuming the window is a rectangle) is A = LW, where A = area, L = length, and W = width.

Substitute the values:


\multimap\qquad\bf{A=(5x+5)(2x+6)}

To multiply these binomials, use FOIL (first, outside, inside, last):


\multimap\qquad\bf{A=5x*2x+5x*6+5*2x+5*6}


\multimap\qquad\bf{A=10x^2+30x+10x+30}


\multimap\qquad\boxed{\bf{A=10x^2+40x+30}}


\therefore the area is 10x^2 + 40x + 30.

User Machinery
by
8.4k points
5 votes

Answer:


\sf \textsf{Area of the window} = 10x^2 + 40x + 30

Explanation:

To find the area of the window, we need to multiply its length and width.

The dimensions of the window are given as
\sf 5x + 5 and
\sf 2x + 6.

The area (
\sf A) is given by:


\sf A = \text{Length} * \text{Width}

Substitute the given expressions for length and width:


\sf A = (5x + 5) * (2x + 6)

Now, use the distributive property to multiply:


\sf A = 5x * (2x + 6) + 5 * (2x + 6)


\sf A = 10x^2 + 30x + 10x + 30

Combine like terms:


\sf A = 10x^2 + 40x + 30

So, the area of the window is
\sf 10x^2 + 40x + 30.

User Underfrog
by
8.9k points

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