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The visible colors listed from shortest to longest wavelength are violet, blue, green, yellow, orange,

and red. Which of the following accurately compares the frequency of these colors using this
information?
A.Blue has a higher frequency than violet.
B.Orange has a lower frequency than red.
C.Violet has a lower frequency than yellow.
D.Blue has a higher frequency than green.

User TechnoTech
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1 Answer

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Final answer:

Colors in the visible light spectrum can be ordered by wavelength from shortest to longest as violet, blue, green, yellow, orange, and red, with violet having the shortest wavelength and red the longest. Inversely, for frequency, red has the lowest and violet the highest. Blue has a shorter wavelength and higher frequency than green, but a longer wavelength and lower frequency than violet.

Step-by-step explanation:

When arranging the colors yellow, blue, and red by their wavelengths, they follow this order from shortest to longest: blue, yellow, red. This is because in the visible spectrum, colors are arranged as violet, blue, green, yellow, orange, and red, with violet having the shortest wavelength and red the longest. For frequencies, the arrangement is opposite to that of wavelengths.

Considering that frequency and wavelength are inversely related, the order from lowest to highest frequency would be red, yellow, blue, where red has the lowest frequency and blue has the highest. This relationship is consistent with the phenomena of the visible light spectrum where shorter wavelengths correlate with higher frequencies.

The visible colors follow this pattern due to the nature of light as an electromagnetic wave, where wavelength and frequency are inversely proportional according to the equation c = λf (where c is the speed of light, λ is wavelength, and f is frequency). Therefore, the color blue, situated between green and violet in the visible spectrum, has a higher frequency than green but a lower frequency than violet.

User AnglimasS
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