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If trapezoid JKLM is translated according to the rule (x, y) → (x + 5, y − 4), what are the coordinates of point L'?

1.(3, −3)
2.(1, −6)
3.(8, −6)
4.(−1, 3)

User SDD
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1 Answer

6 votes

Final answer:

The coordinates of point L' after the translation are (4, -1).

Step-by-step explanation:

To translate the trapezoid JKLM according to the rule (x, y) → (x + 5, y − 4), you need to add 5 to the x-coordinate and subtract 4 from the y-coordinate of each point. Let's see how this rule applies to point L. The original coordinates of L are (x, y) = (-1, 3). Applying the translation rule, the new coordinates (x', y') of L' would be:

x' = x + 5 = -1 + 5 = 4

y' = y - 4 = 3 - 4 = -1

Therefore, the coordinates of point L' after the translation are (4, -1). So, the correct answer is 4.(4, -1).

User Asim Mahar
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