Question

Which of the atoms would ionize to form to become a -2 anion? *
Be
Se
Rb
Br

Answer 1

Selenium (Se) would ionize to form a -2 anion as it is in group 16 of the periodic table.

Step-by-step explanation:

The atom that would ionize to become a -2 anion among the given options (*BeSeRbBr) is selenium (Se). Selenium is located in group 16 of the periodic table, where atoms tend to gain two electrons to achieve the electron configuration of the next noble gas, forming a 2- charge. Other options like beryllium (Be), rubidium (Rb), and bromine (Br) do not form -2 anions; Be tends to form a +2 cation, Rb a +1 cation, and Br typically form a -1 anion as it is a halogen in group 17.