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What is the momentum of a 22 g swallow going 5.2 m/s (0.11 kg m/s)

User Lechup
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Final answer:

The momentum of a 22 g swallow going 5.2 m/s is 0.1144 kg·m/s, which can be rounded to 0.11 kg·m/s.

Step-by-step explanation:

The momentum of a 22 g swallow going 5.2 m/s is calculated by using the formula for momentum, which is p = mv, where p is momentum, m is mass, and v is velocity. The mass of the swallow should be converted into kilograms by dividing the given grams by 1000. Thus, the mass of the swallow in kilograms is 0.022 kg.

Now, we multiply the mass (0.022 kg) by the velocity (5.2 m/s) to find the momentum.

Momentum, p = 0.022 kg × 5.2 m/s = 0.1144 kg·m/s, which we can round to 0.11 kg·m/s as per the information provided in the question's parentheses.

User Jpgeek
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