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A cement mixer has a radius of 2.5 m and takes 50 seconds to make one revolution.

A) What is the acceleration of a piece of dried cement (0.010 kg) on the inside wall of the mixer?
B) What is the net force on it?

User Stix
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1 Answer

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Final answer:

The acceleration of a piece of dried cement on the inside wall of the mixer is approximately 0.0395 m/s², and the net force on it is approximately 0.000395 N.

Step-by-step explanation:

To calculate the acceleration of a piece of dried cement inside a cement mixer, we need to find the centripetal acceleration which is given by the formula a = (v^2)/r, where v is the linear speed and r is the radius of the circular path.

First, let's find the linear speed v using the relationship v = 2πr / T, where T is the period of one revolution. Given the radius r = 2.5 m and T = 50 s, we get v = (2π * 2.5 m) / 50 s. Calculating this, v is 0.314 m/s. Now we can find the centripetal acceleration a = (0.314 m/s)² / 2.5 m, which is approximately 0.0395 m/s².

The net force F acting on the cement piece can be found using Newton's second law, F = ma, where m is the mass of the cement piece. Given m = 0.010 kg and the calculated acceleration, F = 0.010 kg * 0.0395 m/s², which is 0.000395 N.

User Brent Schooley
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