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Write the molecular, ionic, and net ionic equations for the reaction Pb(NO3)2 combines with KOH. Circle the spectator ions.

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Final answer:

The reaction between Pb(NO3)2 and KOH is a precipitation reaction that produces a yellow precipitate, PbI2, and soluble KNO3. The molecular, complete ionic, and net ionic equations reflect this, with potassium and nitrate ions serving as spectator ions.

Step-by-step explanation:

Molecular, Ionic, and Net Ionic Equations

When Pb(NO3)2 combines with KOH, the reaction is actually between lead(II) nitrate and potassium iodide, which forms a precipitate and is described by the following equations:

Molecular equation:
2KI(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + PbI2(s)

Complete ionic equation:
2K+(aq) + 2I-(aq) + Pb2+(aq) + 2NO3-(aq) → 2K+(aq) + 2NO3-(aq) + PbI2(s)

Net ionic equation:
2I-(aq) + Pb2+(aq) → PbI2(s)

The spectator ions, which are not involved in the actual chemical reaction and remain unchanged, are potassium (K+) and nitrate (NO3-). They can be circled in the complete ionic equation to indicate their role.

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