Final answer:
The reaction between Pb(NO3)2 and KOH is a precipitation reaction that produces a yellow precipitate, PbI2, and soluble KNO3. The molecular, complete ionic, and net ionic equations reflect this, with potassium and nitrate ions serving as spectator ions.
Step-by-step explanation:
Molecular, Ionic, and Net Ionic Equations
When Pb(NO3)2 combines with KOH, the reaction is actually between lead(II) nitrate and potassium iodide, which forms a precipitate and is described by the following equations:
Molecular equation:
2KI(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + PbI2(s)
Complete ionic equation:
2K+(aq) + 2I-(aq) + Pb2+(aq) + 2NO3-(aq) → 2K+(aq) + 2NO3-(aq) + PbI2(s)
Net ionic equation:
2I-(aq) + Pb2+(aq) → PbI2(s)
The spectator ions, which are not involved in the actual chemical reaction and remain unchanged, are potassium (K+) and nitrate (NO3-). They can be circled in the complete ionic equation to indicate their role.