Question

How many moles of water are produced from the reaction of oxygen with four moles of propane (C3H8)? C3H8 + 5O2 --> 3CO2 + 4H2O

Answer 1

When four moles of propane react with oxygen according to the provided chemical equation, 16 moles of water are produced through stoichiometric calculations.

Step-by-step explanation:

The student wants to know how many moles of water are produced from reacting oxygen with four moles of propane (C3H8), according to the equation C3H8 + 5O2 → 3CO2 + 4H2O. From the balanced chemical equation, we can see that 1 mole of propane produces 4 moles of water. Thus, if we react 4 moles of propane, we can apply the stoichiometry of the reaction as follows:

4 moles C3H8 x (4 moles H2O / 1 mole C3H8) = 16 moles H2O

Therefore, when 4 moles of propane combust with oxygen, 16 moles of water are produced.

Answer 2

Step-by-step explanation:

The reaction is:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

We see, that the equation is ballanced.

As we have data from only one reactant, we assume the other is in excess.

Ratio is 1:4 (stoichiometry). We solve this, by a rule of three:

1 mol of propane can produce 4 moles of water

Then, 4 moles of propane, may produce

( 4 . 4 ) /1 = 16 moles of water can be made.

Remember, we always have to work with the limiting reactant.