Final answer:
The skier's weight perpendicular to the slope is found by calculating the normal force, which is the weight (W) times the cosine of the slope's angle. For a skier with a mass of 65 kg on a 35-degree slope, the perpendicular weight is approximately 522 N.
Step-by-step explanation:
To find the skier's weight perpendicular to the slope, we need to calculate the normal force, which is the component of the skier's weight that acts perpendicular to the slope. Since the skier has a mass of 65 kg and the slope is at a 35-degree angle, we can use the relationship Wy = W cos(θ), where Wy is the perpendicular component of weight, W is the weight, and θ is the angle of the slope.
The weight W of the skier is given by the equation W = mg, where m is the mass and g is the acceleration due to gravity (9.8 m/s2). This gives us:
W = 65 kg × 9.8 m/s2 = 637 N (approximately)
Now, we calculate the perpendicular component of the weight:
Wy = 637 N cos(35 degrees) ≈ 637 N × 0.819 = 522 N (approximately)
Therefore, the skier's weight perpendicular to the slope is approximately 522 N.