Question

Norman must make 20 party grab bags for a total cost of less than $75. 20. Each grab bag contains an identical fruit bar and an identical prize. Which inequality can be used to model the situation? Let f be fruit bars and p be prizes?

Answer 1

The inequality to model the situation for Norman's grab bags is f + p < 75, where f is the cost of 20 fruit bars and p is the cost of 20 prizes, ensuring the total cost stays under $75.

Step-by-step explanation:

To model the situation where Norman must make 20 party grab bags for a total cost of less than $75, and each grab bag contains an identical fruit bar and prize, we can use the inequality f + p < 75, where f is the cost of 20 fruit bars and p is the cost of 20 prizes. This inequality ensures that the combined cost of fruit bars and prizes for the 20 grab bags stays below the $75 threshold.

To make it perfectly clear, if we let f represent the total cost of 20 fruit bars, and p the total cost of 20 prizes, then each fruit bar and prize would cost f/20 and p/20 dollars respectively. Therefore, the inequality representing the total cost of 20 grab bags would be f/20 + p/20 < 3.75, because each grab bag must cost less than $3.75 (75 dollars for 20 bags) for Norman to stay under his budget.