Question

A plane starts from rest and accelerates uniformly over a time of 30 s for a distance of 150m. Determine the plane’s acceleration.

Answer 1

To find the plane's acceleration, we use the kinematic equation for uniform acceleration, resulting in an acceleration of \(0.33m/s^2\) for the plane over a distance of 150m in 30 seconds.

Step-by-step explanation:

To determine the plane's acceleration, we can use the formula derived from the basic kinematic equations for uniform acceleration. This formula is given by:

\(a = \frac{2 \cdot (d - v_i \cdot t)}{t^2}\)

where:

• \(a\) is the acceleration
• \(d\) is the displacement or distance traveled
• \(v_i\) is the initial velocity
• \(t\) is the time taken

In this problem:

• \(d = 150m\)
• The initial velocity \(v_i = 0\) since the plane starts from rest
• \(t = 30s\)

Using the formula:

\(a = \frac{2 \cdot (150m - 0 \cdot 30s)}{(30s)^2} = \frac{300m}{900s^2} = \frac{1}{3}m/s^2\)

Thus, the plane's acceleration is \(\frac{1}{3}m/s^2\) or approximately \(0.33m/s^2\).